[HackerRank][Python3] Sherlock and the Valid String
2018. 7. 15. 02:33 |
프로그래밍/HackerRank
Problem :
https://www.hackerrank.com/challenges/sherlock-and-valid-string/problem
My Solution :
#!/usr/bin/env python3 from collections import defaultdict def isValid(s): char_dic, count_dic = defaultdict(int), defaultdict(int) for char in s: char_dic[char] += 1 for count in char_dic.values(): count_dic[count] += 1 if len(count_dic) == 1: return 'YES' if len(count_dic) > 2: return 'NO' m, M = sorted(count_dic) if count_dic[1] == 1: return 'YES' if M - m == 1 and count_dic[M] == 1: return 'YES' return 'NO' s = input().strip() result = isValid(s) print(result)
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